Calculating a Limit by Multiplying by a Conjugate
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Uploaded on Apr 12, 2008
Calculating a Limit by Multiplying by a Conjugate. For more free math videos, visit http://PatrickJMT.com
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Uploader Comments (patrickJMT)
seb090495 7 months ago
I would die without you. I spend hours on your videos before calculus tests
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patrickJMT 7 months ago
glad you like them :)
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mthfku 8 months ago
How come I`ve never seen your vids before? Life saviour!
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patrickJMT 8 months ago
i dunno :)
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N1G3L2 8 months ago
what the hell...little wayne advertisements at the beginning of a calculus tutorial..really youtube?
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patrickJMT 8 months ago
lol, he must be targeting the math crowd :)
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Top Comments
patrickJMT 1 year ago
i practice for one hour each day
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All Comments (218)
loisalove 1 week ago
How come multiplying the two radicals (square root of x + 2) causes them to cancel out? wouldn't you multiply what is inside the radical, therefore giving you the square root of x^2 + 4x + 4?
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Sim Sidhu 4 weeks ago
YO
I LOVE YOU MATH
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Abigail H 1 month ago
Thank u so much :)
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Jasmine Singh 2 months ago
I honestly would've been screwed for my test tomorrow. Thank you for the video! greatly appreciated!
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Toby durrough 3 months ago
saved a nite buddy.
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art martin 3 months ago
Thanks Patrick. Your videos are truly a tool to succeed.
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Senna Hassan 5 months ago
thank you your videos on limits really helped me understand our professors last lecture which i was having trouble with :)
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Nick Marcella 5 months ago
could you use L'hopital's rule here?
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WeThreeKingz 6 months ago
You sir, have saved my Calculus grade, and my chances of getting Halo 4.
Subscribed, liked, favorited.
I also ask for your permission to promote you in videos that I make. Contact me for more details. :D
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AndyAngelZ 6 months ago
How would I solve the problem if the 3 was another radical??? how would you do this problem if there were 2 radicals?
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