Gauss's Law and Concentric Spherical Shells

Introduces the physics of using Gauss's law to find the electric fields around concentric spherical shells. This is at the AP Physics level.

Category:

Science & Technology

Tags:

• concentric spherical shells
• Gauss's law
• AP Physics

[JustinLuysMom]

You are my last hope to pass my physics midterm.

[HouseOfZafar]

I think in the outer thick shell, E=0 because if you enclose a Gaussian surface over the entire thing, we have +Q in the middle, and the small negative charges must add to -Q, hence total enclosed field, E=0. For the middle sphere, I think he is wrong, but he may have a point with the outer thick shell.

[HouseOfZafar]

I think he assumed the inner sphere is a shell, hence not solid. But as the previous video shows, a solid sphere with charge DOES have E>0

[Kuahana03]

No I meant that in the following video after this you explain that the E outside the concentric sphere isn't 0 but in this video you say that E=0 on the outside of the concentric sphere.

[Kuahana03]

@stephenxluo Yes i agree i was well confused did he make a mistake in this one with that then.

[runeruly1]

I wish i could borrow your brain for my exam

[stephenxluo]

@tipps1080 q enclosed doesn't equal 0. E is 0 because of your second statement.

[TheDoughnut93]

@chihuahuabebi Why is that so?

[osmium13]

thanks so much! this helped me understand the base concepts for another problem i was having difficulty with. Your help is truly appreciated!

[chihuahuabebi]

Electric Field Inside a Charged Solid Sphere is NOT zero!!!! You are wrong!!!

[cherryonion]

If C is a conductor there should be charge at both B<R<C AND C<R!