Equilibrium & ICE Tables.wmv
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Uploader Comments (peterr27)
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All Comments (22)
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what if there was a solid in the products or the reactants??
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Thank you my friend, I now have a 45% chance of passing my mid term.
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Studying ahead for next semester, and this helped me with a confusing explanation from the book. Thank you.
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THANKYOU!!!!!
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Thank You for the great explanation! Helped out a lot!!
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Thankss, now i know what to do on the exam! :)
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Great video!! Chem 12 test tomorrow and reviewing with this really helped :)
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Pure solids and pure liquids have concentrations that are difficult to express (molar density?) and cannot be changed so they are simply left out of any equilibirum expression. Do I have Ksp video?
peterr27 1 week ago
howd he get the -0.0503
jf1gd2 1 month ago
@jf1gd2 There is 1:3 stoichiometry between N2 and H2. So, if H2 is decreased by 0.151 then N2 must be decreased by one third that much . . . 0.0503.
peterr27 1 month ago
I have a double displacement reaction and it only gives me the moles for the reactants...do I put 0's in both spots(for the products) for the initial concentration? Thanks :)
ShonieShanya 4 months ago
@ShonieShanya yep
peterr27 4 months ago
what if u only get initial concentrations and none at equilibrium...use limiting reagent as x??? and solve? example plz.
neverowned1 1 year ago
@neverowned1 You'll have to determine which way the reaction will shift based on solving the equilibirum expression for the values given. After that, plug in (initial concentrations - x) on the side that will decrease and (initial concentrations + x) on the side that will increase - mind the stoichiometry (maybe 2x, 3x, etc.) After that, it's just algebra. Sorry, no time to post an example.
peterr27 1 year ago