Logarithms : Equations 1 : ExamSolutions

In this tutorial I show you how to solve equations where the unknown is a power by using the power rule for logarithms. This tutorial can be viewed in a larger and clearer form on the ExamSolutions website. To see this and others on logs go to http://www.examsolutions.co.uk/maths-tutorials/Logarithms/logarithms_contents...

Category:

Education

Tags:

• logs
• logarithms
• equations
• ExamSolutions
• exam
• solutions

[SuperLittlesunshine7]

you've been a GREATTTT help. I was never able to grasp maths, but.... let you know my test grade! :)

[ExamSolutions]

@SuperLittlesunshine7 Cool

[feastsinmalta]

for question 2 cant you use the log rule 'log 3 + log 5' becomes 'log (3*5)' = 'log 15' ??

[ExamSolutions]

@feastsinmalta Yes you can

[NRGxPHlL]

I don't know if you're aware but, for OCR atleast, they ask for most rounding to be done to 3SF, you usually do 1DP. Don't know if any marks are awarded for it but it could potentially be a loss of marks for someone.

[ExamSolutions]

@NRGxPHlL Yes I am aware but I cannot cover all boards on their required accuracy so i use my own.

[Menacin]

hi there, are your log vids based on c2? because on your site there arent any logs and exponentials under c2.

Thank you

[devstaralmighty123]

excellent teacher

:)

[DaruiAkaBlackNinja]

easy way for for first one use that button on top right below "ON" as =log(base 3) 12

[iYateszy]

@bollywoodmassive his answer of 2.3 was only to 1dp, if he used the full answer that was on his calculator so 3^2.26185... it would be 12.

[zehrazaidi246]

wonderful explanation

[bollywoodmassive]

just another thought, in the first part you got the answer 2.3, but if you do 3^2.3 then you get 12.513... so wouldn't that round up to 13?