I finally connected my xray machine transformer up and tested it out. This demo is using about 60kV not the full 100kV rating. I will soon post a video when I dare to go that high!
@MrGoogfan Then how could the SIBNIIE Marx generator have made a 70-meter spark with just 5MV? I don't want to argue, but 100kV will surely jump much further than 10cm with pointy electrodes (wires etc.)
@MrGoogfan 60kV has 60*1.41= cca 85kV peak voltage, which according to this rule would fire at 8.5cm. But with such high voltages pre-ionisation takes place, and the spark can jump further.
However the voltage says nothing on how far you can draw out the spark, eg. a MOT has only 2kV but you can draw 12cm arcs out of it.
how much did the transformer cost you?
mimic58 1 year ago
@jmartis2
about 14-15cm
MrGoogfan 1 year ago
@MrGoogfan That sounds right. How far does it jump with wire/needle electrodes?
jmartis2 1 year ago
Well, my 100kv will only jump 11 cm with 1" ball electrodes.
MrGoogfan 1 year ago
@MrGoogfan Then how could the SIBNIIE Marx generator have made a 70-meter spark with just 5MV? I don't want to argue, but 100kV will surely jump much further than 10cm with pointy electrodes (wires etc.)
jmartis2 1 year ago
@jmartis2
I said spark, not arc. Sparks are instantaneous, arcs are drawn out.
Pre-ionization does not really have any effect, because ionized o2 immediately turns to neutral, yet unstable 03.
MrGoogfan 1 year ago
@MrGoogfan 60kV has 60*1.41= cca 85kV peak voltage, which according to this rule would fire at 8.5cm. But with such high voltages pre-ionisation takes place, and the spark can jump further.
However the voltage says nothing on how far you can draw out the spark, eg. a MOT has only 2kV but you can draw 12cm arcs out of it.
jmartis2 1 year ago
@jmartis2
actually, 10kV gives a roughly 1cm spark. So 60kV is only 6cm
MrGoogfan 1 year ago
yeah electricity is kinda weird, like every 10kv higher, everything changes. idk, you just gotta estimate i guess
thats a smart formula though, it took me a minute to understand it (not very good at math)
kalebman5000 3 years ago
I have worked out this arc length formula:
L=V*sqrt(I)*4
where L arc is length in cm
V is open circuit voltage in KV
I is short circuit current in amps
only it does not seem to work on very high voltages (30KV+) or very low currents
jmartis2 3 years ago