L'Hopital's Rule I
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Top Comments
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awesome.
learnt more in 4 minutes than i did in a few clases with my dingbat of a teacher
2 years ago 13
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Wow, thanx, for the past few days I've been staring at random conglomerations of integers and derivatives and limits.
Somehow in 4 minutes everything came together in a very "A Ha" type moment. Thanx
3 years ago 7
All Comments (29)
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Royal, shiny cock
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good vid
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You're a great teacher! Thanks!
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@sPYrOs5050 neither is your comment you know :/
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these are all easy ones -_-
one's form the homework involve limits of log functions which i'm not getting
lim_x->0 (1/x)ln( (e^x-1) / x
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dingbat... goodness haven't heard that in while!
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Great video thanks!
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you're the man dude, thanks for posting
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you rock man, finally got l'hopitals rule!
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god damn.... very helpful. ^^
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for the example at 2:15: why wouldn't you repeat l'hopital's rule 2 more times, in a similar fashion to the last example. this would give you (e^x)/6 or 1/6?????
gensulitor 2 years ago
@gensulitor L'Hopital can't be applied again because after doing it once, the result is no longer indeterminate. After doing it once, when you try to plug in 0, you get 1/0, which means the function has a vertical asymptote.
calctube 2 years ago
x^2-4 = (x-2)(x+2). Much easier than L' Hospital's rule. Plus you are calculating really quick. This is not helpful you know :/
sPYrOs5050 2 years ago
@sPYrOs5050 I know the factoring way is easier. It was just an example.
calctube 2 years ago