Limits Involving Absolute Value

Limits Involving Absolute Value - In this video I do two limit problems that involve | absolute value | . I discuss the basic algebraic idea of how to get started on these problems.
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[Shy Davis]

I'm a little confused. Lets say the lim x-> -3+ Ix+1I/x^2 - 9. When I broke it down I got 2/0 and -2/0. Is my answer: it does not exist because there is a '0' in the denominator or is it negative and positive infinity? (based on it being an absolute value problem). @patrickJMT

[patrickJMT]

if the left hand limit and right hand limit are not the same, the limit does not exist. a limit can not have two different values.

[Kit Carson Henderson]

9:40

"2/x is just gonna be a shit uh or a stretch"

lolololol

[ThePieStoreGuy]

Only a Sith deals in absolutes.

[AhMaDoV08]

You are THE BEST!!

[Shubham Soni]

sir,your videos are awesome and very helpful for me i have a problem in one Ex. please help me............... Discuss:

F(x) = |x-1|+|x-2| at x=1 and x=2.

[Mario Balotelli]

your voice has gone weird

[syanaz bazil ahmad kamal]

THIS IS MINDBLOWING everything make sense thanks!

[Brutalwillis]

Isnt a limit equaling +- infinity actually non-existent?

[Jaclyn Hernandez]

This was so helpful! You're a great teacher. Thank you so much!

[primmanet]

lim( x->0+) of the same function = 0

[Kieran Hughes]

The way you broke this down was much better than how I was taught. You explained it in a way I could understand, and now I feel confident in ace-ing my test tomorrow. I only got 46% on my first try, and luckily I have a chance at a retest tomorrow. 100% here I come!

[sarsuraaa]

hey you are an amazing teacher !!!!

just a question i don't get why we ignore the denominator, why do we just concentrate on the absolute value ?? like in the second example if we plug 0 we'll get 1/0 which gives a 0/0 limit but instead we just concentrated on the absolute value part

[MeanGreenTX94]

You saved my Calculus grade. Thank you!