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Boolean Algebra: De Morgan's Laws

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Uploaded by on Jan 12, 2009

A discussion of De Morgan's Laws:
(ABC)' = A' + B' + C'
(A + B + C)' = A'B'C'

Hope you understand and enjoy

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Education

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  • likes, 7 dislikes

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Uploader Comments (Russoft)

  • a.b.c + a.b.c = a.b how to prove this ?

  • @krishkishore100 you can't prove it, it's not true. Make a truth table and you'll find both sides don't equate.

  • yo great explinations but in uk we have differant symbols for that comma thing you use and also theres some other method for de morgans which im kinda stuck on, but many people still understand ur vid so it obv make sense lol im jus tryin to look for a "british" method lool

  • @apakiboi notation for a lot of mathematical concepts vary from school to school which can make it hard to find help on the internet for it. I found this especially true in my last year of my degree. The internet became almost useless.

  • Dont know if its right but I think your second example is wrong. Im pretty sure its ABC all not not seperate nots. LAW 13 break the line change the sign

  • are you referring to the law: (A+B+C) = A'B'C'? Or something else?

Top Comments

  • your good in explaining, will you explain the "karnaugh map".

  • very good, you showed me in 8 mins what my lecturer failed to in 4 hours lool

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All Comments (49)

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  • @apakiboi You seem stuck with English, also.

  • Thank you so much!! It's really helpful!! :)

  • saved my life for my test 2moro than:)

  • I think you are making it more confusing

  • i'm sorry this explanation is not really what i'm looking for

  • I agree explained really well thanks for the upload

  • In his final example, could you simplify it furthur too (A'+B') + C'D' ?

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