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Uploaded by on Jan 27, 2008

You will see the readings I got off of 3 different sources from the simple pulse motor.
Input(pulsed) 12.19v * .057a = .7watts
Output 1(alternator):
8.3v * .100a = .83watts
Output 2(Back EMF):
10.10v * .197a = 1.99watts
Output 3(secondary coil):
4.86v * .135a = .66watts

Total output= 3.48watts under load!What does this all mean?? I will solder all the connections on a board and label them so we can all play along.
You too can do this at home :)
Good luck!
Todd

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Uploader Comments (ktservicescorp)

  • Something else Todd, just remember that what U R working with is roughly termed Cold Electricity as opposed to Hot Electricity which the majority of electrical engineers are used to, so some of their ideas may actually be adverse to improving your set-up. That said I am like U in that our learning curve is steep to say the least but in some ways it is a good thing we don't understand current laws of electricity as they do NOT fit with these circuits at all! No offense intended to anyone. Peace.

  • I agree...I am trying to understand all this myself. I am trying to mix the two. BEMF, secondary coil winding electricity(cold), and the alternator(hot)

    Todd

  • Hi, I have had some great spikes, I am getting spikes to 288v about every second. Problem I keep frying my reed switches. How do I stop frying my reed switches?

    Thanks.

  • put a relay in between so low voltage on the reed switch triggers the current to the coil.

    Todd

  • I'm sorry to disappoint you but, ac power cannot be calculated by IxV. Especially when there are capacitators and coils involved. Would you please search at wiki for "ac power" and redo all the calculations based on the right formulas. Another flaw is that you don't know the kind of wave theres in the output. I'm pretty sure it has a lot of noise which compromise the measuring of the power. Get an oscilloscope and you'll understand.

    Nice effort anyway, i hope you could learn from your mistakes.

  • Me too...I hope someone who knows much more than I do will try this and give more accurate readings. Thanks for watching and good luck on building something of your own :)

    Todd

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All Comments (40)

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  • @RockManAU So... if you're getting more power out (P=V*A) than you are putting in, why can't you get the motor started, then switch the battery out of the system so it runs off of itself?

  • 12.19v X 0.057A = 0.69483Watts

    he said 57mA NOT 570mA!

    I think you missed off the zero point in your calculations ;)

  • the motor is spinning quite slow, use a brushless motor and the system will be even more effecient.

  • You're pretty much seems to be a very educated in this field. Is there anything you could at least contribute rather than making a point that you know more than we do?

  • I just did the math for this circuit. I wanted it to be overunity but it is still an efficient little motor.

    Total Input wattage - 6.9483W

    Total Output wattage - 3.4758W

    Roughly 50% efficient.

  • first off great job!I was kicking around making one myself and wondered about using a briggs and stratton ignition coil for operating power as it is supposed to put out around 13000v at 250 rpms as you can guess i'm no electrician lol

  • great job!!! i was wondering could i use this circut on my newman machine? would it  work the same?

  • have you tried using a switch mode charging circuit for the batteries, so that you can charge the batteries properly even with a lower voltage input. these are the chargers we use for Remote control hobby.

  • more power from the emf ,mage your alternator into a moter with a second set of windings,and get emf from all sets..

  • As an ex electrical engineer, let me say that one of the courses that you take is "Pulse Circuits" which covers this type of stuff in quite a bit of detail. In another set of postings I mad an offer to Todd to give him some insight into what is going on, it could be fun and interesting.

    The current laws of electricity do indeed fit with these circuits. If you want to discuss, hopefully the net result would be that you could approach future experiments with more insight, and get more out of it

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