Fourier Series - Parsevals theorem
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@yasthatsme , the Fourier series of an even function contains only cosines, i.e., f(x) = a_0/2 + \suma_ncos(nx) and the Fourier Series of an odd function contains only sines. t^2 is even.
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The coefficients for the fourier series of an should be 4(-1)^n/n^2 not n+1 (5:28), set be back an hour trying to figure out was I was doing wrong.
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as t^2 is even bn is zero,
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as t^2 is even bn is zero,
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thanks from chile, i have a test at 7pm! :)
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thanks
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Excellent.. thanks mate
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Why didn't you calculate bn? I must have missed something...
yasthatsme 1 year ago
@yasthatsme its about 5 minutes in. Because fourier is estimate for line t^2 is a graph like \./ (.=origin) and since cos is like \/\./\/\ and sin is like \/\/.\/\/ it makes sense that bn is not needed. I also think its something to do with odd and even functions but i cant remember that much.
burny1 1 year ago