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Fourier Series - Parsevals theorem

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Uploaded by on Mar 14, 2009

Tell me if any problems or errors will be deleted sometime summer 2009 due to some material used. http://www.geocities.com/burnyboy2004/

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Education

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Uploader Comments (burny1)

  • Why didn't you calculate bn? I must have missed something...

  • @yasthatsme its about 5 minutes in. Because fourier is estimate for line t^2 is a graph like \./ (.=origin) and since cos is like \/\./\/\ and sin is like \/\/.\/\/ it makes sense that bn is not needed. I also think its something to do with odd and even functions but i cant remember that much.

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  • @yasthatsme , the Fourier series of an even function contains only cosines, i.e., f(x) = a_0/2 + \suma_ncos(nx) and the Fourier Series of an odd function contains only sines. t^2 is even.

  • The coefficients for the fourier series of an should be 4(-1)^n/n^2 not n+1 (5:28), set be back an hour trying to figure out was I was doing wrong.

  • as t^2 is even bn is zero,

  • as t^2 is even bn is zero,

  • thanks from chile, i have a test at 7pm! :)

  • thanks

  • Excellent.. thanks mate

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