calculus fundamental theorem part ii proof (1 of 2)
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Why does this guy remind me of Donkey Kong?
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you're right it can be c actually f(c)=F'(c) but the thing is that the c you're lookin for is the one where f(c)=F'(c) but also = [F(a)-F(b)]/[b-a]
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this guy scares me he is really built
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i finally understand how integration and defferentiation (sorry for spelling) actually become inverse of each other like addition and subtraction
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Oh, ok. Well, yes then. I'm sure it could be equal to c, it's just a 'dummy variable'. No matter what the function is defined as, the variable shouldn't matter, as long as the funcion notation is correct. If you need anything just let me know mildcheddarcheese.
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"Let f(x) = d/dx(F(x))"
As far as I can tell that's the same thing as "Let f(x) = F'(x)" where x could be any number, including c. If I'm wrong, I'd like to know, it will help me in the future.
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Really nice proof!
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for real this guy doesnt look like a math teacher. he looks more like a physical ed teacher!!!
bangalirussian 3 years ago 8
you are awesome! you dont look like a math teacher, dont dress like a math teacher, but you know exactly what you are talking about.. I give me respect! :)
byte1988 2 years ago