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Lec 3 | MIT 5.60 Thermodynamics & Kinetics, Spring 2008

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Uploaded by on Dec 12, 2008

Lecture 03: Internal energy, expansion work.
View the complete course at: http://ocw.mit.edu/5-60S08
License: Creative Commons BY-NC-SA
More information at http://ocw.mit.edu/terms
More courses at http://ocw.mit.edu

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  • bravo!

  • fuckers dude. If i could afford to go to MIT, I would yell out if I knew the answer. I yell out the answer at a community college turned university!!

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  • @HPPcello2 we covered everything they've gone over 3 lectures in during my first lecture

  • they move really slow at MIT

  • Video ends at 9:00 :(

  • I totally understand the prof. Same thing in my school:that we never care to answer questions that we know the answers of...

  • These videos are 100 times better than the book I spent $200 on.

  • @markomiz but yeah sloppy and ambiguous..especially when saying dT=w/cp

  • @markomiz Yeah definitely..Then again i don't think he actually ever says that the heat converted is mgh, he just says that the work done in bringing the mass from h to 0 is mgh. He does say work is converted to heat but he doesn't explicitly say mgh is converted, does he? But i agree that the work converted to heat should be mgh-KE of mass at 0

  • this guys isn't as good as the other one, nice chap, but he is forgetting to repeat the answers as a person who is use to being video taped would.

  • @markomiz

    You are correct. I concede. I misinterpreted the diagram. I assumed the wheel was actually a pressurized turbine, the difference of pressure between which and the external would have contributed to the resistant forces.

  • @DerSchreiFalke the floor point is irrelevant. But if it will make you happy replace "floor" with "centre of gravity of the body pulling the weight down"

    For the kinetic energy to reach 0 the resistance to motion by the fluid on the paddle must be greater than the gravitational force on the weight - impossible, think of a simpler case; pushing a box on a floor with set friction - however you push the box on the floor, the frictional force can never exceed the the pushing force. think about it

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