Fibonacci Formula (TANTON Mathematics)

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Uploaded by on Mar 9, 2010

The Fibonacci numbers begin 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, .... What's the 100th number in this list? The 587th number?

In this video we derive a general formula the N-th Fibonacci number.

(WARNING: This video assumes complete familiarity with solving a quadratic equation, basic properties of exponents, and solving a tiny system of equations.)

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Education

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Uploader Comments (DrJamesTanton)

  • where did u get

    a= # / sqr( 5) ?

  • @heladobon

    Okay: So we have: a + b = 1 and a*phi + b*tau = 1. Multiply the first equation through by tau and leave the second alone.

    a*tau + b*tau = tau

    a* phi + b*tau = 1

    Subtract to get: a(phi - tau) = 1-tau.

    But phi-tau = sqrt(5) and 1-tau = phi (check this!) so we have: a*sqrt(5) = phi giving a = phi/sqrt(5).

    Does this help? [Writing math in an e-mail format horrible!!]

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  • I know it has been a long time since you put this video up. But could you please explain to me how you get

    b = - tau / sqrt(5)

    Because I am trying to work through it myself and I keep getting

    b = tau / sqrt(5)  [Notice the positive tau]

    I must be going wrong somewhere but I don't know where.

    Thanks

  • @DrJamesTanton

    thanks a lot man =D

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