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Multiplying Monomials

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Uploaded by on Jan 4, 2009

The following lesson looks at Multiplying Monomials. Download for FREE and watch on Full Screen using iTunes, by typing the word "Papapodcasts" in the search window. Thank you for watching.

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  • What if you have different variables like 3a^2x^2)(4a^3y^4

  • @Madddoggydog It doesn't change. Remember that the part of adding the exponents only works if the letters are the same otherwise just combine all the terms, writing them all side by side.

    Mr.P

  • how about when the number is outside the bracket?

    example: (a^3x^2)^4

  • @DazzleRush Multiply the 4 with all the exponents inside the brackets. Good luck with your studies.

    Mr.P

  • thanks i actually learned more from this 5minute video than i class..but i have a few problems what if their is some letters and numbers outside the ( ) for example

    C^3 D^2 (C^2 D - 2D) and also how would you subtract the 2D ? please try to reply as soon as possible

  • @PainlesSuicidE You'll have to use distributive law to multiply the C^3D^2 with both terms inside the brackets. So combine the C^3 and C^4 and the D^2 and D together to give you C^7 D^3. Now combine C^3 D^3 with the -2D and you get 2C^3 D^3. The 2 in front of the C^3 came from the 2D. Always put these coefficients in front of the variable terms. I hope this helped, but personally in math, it's easier to show it than explain it in words. Good luck with your studies.

    Mr.P

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  • how do you do somthing like (-7ab^4)^3[(2a^2c)^2]3? please reply!

  • When the exponent is outside the bracet, and you multiply it in with all the numbers, does tht also include the base number or just the exponents?

  • catholic schoool?...oxymoron

    

  • @TheJeterfan223 No your mistaken. You are right with the answer 15x^5. This is what your teacher probably was trying to get at. Let's make a modification to the question and re-write it as: (3x)(5x). Notice how there are no exponents, however, there really is an imaginary exponent and that is the 1. So this answer would be 15x^2, as both x's without a showing exponent, really has a 1 for an exponent. Hope this clears things up for you.

    Mr.P

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