ARM Powered Nokia/LEGO Speedcuber

Not just another LEGO/Nokia Rubik's cube solver! This one has more ARM's!...

Category:

Science & Technology

Tags:

• Speedcuber
• ARM7TDMI
• ARM7
• Classic
• Symbian
• Technologies
• ARM Powered
• ARM processor
• LEGO Mindstorms NXT
• Nokia N95
• N96
• N97
• Rubik's Cube Solver
• Rubiks
• LEGO technic
• mobile phone
• embedded applications
• speedcubing

[blackbirdflight]

what happens if u colour one extra piece red?

[stabilizeYourself]

@MaxMuenker

Why should it be a trick. there's a solving algorithm for the cube. You just need a cam to recognize the faces, feed it to the solver and send the solution to the machine that will apply it to the cube.

[ieatscience]

even if its slow, its faster then me for sure...

[IAssemble]

@IMNOTCRAZY1 and have you seen CubeStormer II ? :D

[IMNOTCRAZY1]

The Cubestormer is still cooler.

[stepmuel]

at 0:49, it stumbles. I know, its probably a software problem, but how is this any good to promote ARM? :-)

[stabilizeYourself]

@Ffiti2

Sorry, but you're wrong. You may want to read the definition of an algorithm. And btw. that machine there solves the cube. How do you think does it that? Every Turing-complete machine does it the same way: it computes algorithms. Even the selection on a fitting algorithm for a pattern is an algorithm itself. :)

[Ffiti2]

@stabilizeYourself Well, I mean there's not "AN algorithm" to solve it; i.e. there isn't one thing that you repeat over and over to solve any cube. If that's not what you mean, then I'm sorry.

[IAssemble]

@stabilizeYourself actually there are some errors that can be corrected if an assumption is made that only a single error is present. For example if all corner pieces were detected correctly except one and for that corner piece only two of the three faces form an expected combination, the software can ignore the detected colour of the third face and correct it based on the colour of the other two faces and the other seven complete corners.

[stabilizeYourself]

@blackbirdflight

Then it wouldn't be a valid cube. Period.

And i guess it would be futile to count the pieces of every color, since you cannot tell _which_ piece was changed. But maybe you could implement a heuristic... First sentence holds whatsoever.

[stabilizeYourself]

@Ffiti2

I don't get your point. What are you trying to tell me? Of course you know since there's an algorithm for it.

[Ffiti2]

@stabilizeYourself You're being really naive. I actually know how to solve the cube...