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Uploaded by khanacademy on Nov 7, 2011
u18_l1_t1_we2 Exponential Application
Education
LICENSE: Creative Commons (Attribution-Noncommercial-No Derivative Works).
For more information about this license, please read: http://creativecommons.org/licenses/by-nc-nd/3.0/.
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this is algebra, college algebra math 1111
viacalvy 3 months ago in playlist More videos from khanacademy
@PSPhacking2009 I'm not from England, but from a few Google searches, I'd say GCSE.
Shadowriku40 3 months ago
I tried to compare what would be cheapest: Compounding once a year, once a month or once a day. It turned out that the less often you compound, the cheaper your loan becomes. Can you explain that so it makes sense intuitively?
Here are the calculations and results:
4000*(1 + (0.03/1))^(1*5) = 4637.0962972000
4000*(1 + (0.03/12))^(12*5) = 4646.4671262211
4000*(1 + (0.03/365))^(365*5) = 4647.3083246046
TomislavDugandzic 3 months ago
in england (UK) what level of education would this be on? GCSE or A level?
PSPhacking2009 3 months ago
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this is algebra, college algebra math 1111
viacalvy 3 months ago in playlist More videos from khanacademy
@PSPhacking2009 I'm not from England, but from a few Google searches, I'd say GCSE.
Shadowriku40 3 months ago
I tried to compare what would be cheapest: Compounding once a year, once a month or once a day. It turned out that the less often you compound, the cheaper your loan becomes. Can you explain that so it makes sense intuitively?
Here are the calculations and results:
4000*(1 + (0.03/1))^(1*5) = 4637.0962972000
4000*(1 + (0.03/12))^(12*5) = 4646.4671262211
4000*(1 + (0.03/365))^(365*5) = 4647.3083246046
TomislavDugandzic 3 months ago
in england (UK) what level of education would this be on? GCSE or A level?
PSPhacking2009 3 months ago