A plane is on a runway that is a giant conveyor belt. As the plane tries to take off, the conveyor will match the plane-wheels' surface speed, opposing the plane's forward motion.
If the wheels and belt have perfect traction, ie no slipping or skidding, will the plane be able to take off?
This is a variation of a well known physics quiz. The original had the conveyor's speed matching the plane's take-off speed (and the answer was "Yes!").
In this version, the belt's speed B.vx is the same as the wheels' surface speed W.vs, which is the same as (no slipping or skidding) the belt's speed minus the plane's speed W.vx:
B.vx = W.vs = B.vx - W.vx ==: W.vx = 0
ie the plane's speed W.vx is 0, and the plane doesn't move and hence doesn't take off. The belt speed (equal to the wheel surface speed) can be anything though.
With idealized components (indestructable and perfectly rigid wheels and belt, perfect traction but no internal friction, sufficient control systems and power, etc), this version of the quiz has no physical meaning - the plane is defined by the question to stand still.
However, since perfect traction cannot occur in an infinitely small (mathematical) contact point, apart from torque a linear force exists between the wheels and belt, which increases with the belt speed.
This simulation uses six Phyz Logics circuits to measure the belt's and plane's current speeds, and set the belt's new speed to their difference (ie the wheel surface speed).
up2data.se/get/PC.pzs
patentgen 10 months ago
Can you upload the scene file (pzs)?
Kind regards Ryttarinnan
ryttarinnan 10 months ago
@ryttarinnan Sure: up2data.se/get/PC.pzs
patentgen 10 months ago