Calculus: Derivative of x^(x^x)
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How do you find the second derivative?!
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Yo dawg i herd you like x's, so I put a x to the power of x in yo power of x so you can derive while u derive while u derive.
- X to the Z - X(z)ibit.
where Z = X^x
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if you don't replace (1/x)*(x^x) with x^(x-1), you can then factor out an x^x
if you do that and distribute the (ln x) the resulting equation is indeed 'elegant':
Dx[x^x^x] =
x^x^x * x^x ( ln^2 x + ln x + 1/x )
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dude U e a hero :)
thanks a lot
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you are my hero .. thanks :)
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@khanacademy One of my stupid friends from class showed my teacher this video and now she wants us to differentiate the long equation at 8:31... omg...
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THANK YOU! calculus exam in two days and I was so stuck. I'm definitely going to need to keep watching a few more derivative videos before i get the hang of it, but this was so helpful. thank you!
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not that hard, no need to understand a rule from just 2 functions, you differentiate x^(nx) and ur done ^_^
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than you just have to start derivating the complex numbers ... ln(-3) is actually a complex number which more precisely is (i*pi) + the integral from 1 to 3 of (1/x)dx ...
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DUUUUUUUUUUUUDE. Amazing. AAAAAAAMAAAAAAAAZING.
ctw005 2 years ago 28
Great going on the new interface your videos look so much better
DJPirrone 2 years ago 26