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zetafunction_surprise

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Uploaded by on Jan 11, 2009

Unexpectedly, function zeta-odd(1-s)(adding only vectors with odd numbers n) will match perfectly to the course of alternating zetafunction. Zeta-odd(s) may track zeta-alt(s) as well, just multiplied by a calculable factor. With Re(s)=0.5 zeta-alt may by this be tracked by two symmetrical parts of zeta-odd(s) and its konjugated(only for Re(s)=0.5) pendant zeta-odd(1-s). This makes it plausible, that there are infinitely many zeroes for Re(s)=0.5 and there might be none for other values of Re(s). In the meanwhile i found, the symmetry is known, please lok at the article of Carl Erickson:
http://surj.stanford.edu/archives/Index2005.html
More details in the small book-sorry for the price and that it is in German. Thomas.Kromer@t-online.de

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