SAT Lesson 1 - Triangles (P4 of 6)
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Easier way: Make a simle observation, QS=1;QV=3; PT =3; PR =4; from that we have: Area of Tri. PST= 2*3/2=3; and Area of Tri. PQR= 3*4/2=6; then, 3/6=1/2 and your done. You must make smart observations instead of working too hard. On practice exams find the best ways to do each problem, there is always a fast way. Nice vid though.
2 years ago 5
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All Comments (9)
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so ur saying everytime i see this kind of problmes i can choosee random numbers ?
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Wont it be easier with 1 as QS 2 as SV 3 for PT and 4 for PR?
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helpfull but can you go a tad bit faster in u next vids? :)
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I just said SV = 2
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hahah i like your methods man! thanks for your vids
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in the beginning, when u cross multiply, is the 3/4 supposed to be one number?? bcuz if not, wouldnt u multiply the top by 4 and the bottom by 3??
holagurl175 2 years ago
Sorry yo no comprendo... Can you explain your question again? The problem gives us PT/PR=3/4. I just bring the PR to the other side...
MiTeach 2 years ago
is it still gonna work if i just plug in the number that they gave and try to work it out?
zanpaktuh 3 years ago
try and find out! :]
MiTeach 3 years ago
good point, spinningbirdkick1! you could have just substituted in the numbers in the numerator and denominator of the given ratios. but to demonstrate the technique clearly, i wanted to sub in other numbers.
MiTeach 3 years ago