Robotics and Electronics Tutorial - 10 - Building a Circuit
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All Comments (91)
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FYI all of the current does still go through the LED. Current in series is the same. The reason you put a resistor in series with the LED is so there will be a Voltage drop. Power = VI, so because there will be a drop in voltage (due to the resistor), the power disapated by the LED will be less. If you had the LED hooked directly up then ALL of the power disaapated by the circuit would be through the LED and that could cause it to burn out.
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I think there is a lack of intermediate videos on the subject of LED's, Different colors have different voltage drops as well as different current ratings for ideal performance, and these differences should be taken into account when calculating a proper resistor value. Subtract the LED voltage drop from the supply voltage, and then divide the remaining voltage [which is the voltage drop across the resistor] by the ideal LED current, Rt = (Vt - Vled) / Iled.
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Hey! we are so much interested in this area. Can you please make more tutorial for us?
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u helped me out,thanx
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If i was taking a formal class it would have taken a week to get to this point.
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As far as my knowledge, electrons flow from -ve to +ve, in this case u must place resistor on +v or cathode side(blace wire side), there is something really wrong with this experiment isn't it ?
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yo man could u gimmi yo email id?
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@TheHoho001 - Ah, you are correct. Thank you.
this is not plumming dude. it doesn't work that way. it is irrelevant where the resistor is as long as it is in the circuit. Ohms law states it clearly
cyberlord64 2 years ago 18
@crazeycane - For maximum life, the LED should run around 25milliamps. Knowing your voltage, 9v, and your amperage = .025amps, you can use ohms law to calculate R=V/I or 9/.025 = 360ohms
Hope that helped.
BackyardAmusement 11 months ago 6