Electric Field at the Center of a Semicircular Ring of Charge
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awesome... just awesome
Pisceean 1 week ago
can you do for a quarter circle?
solijoli123 1 week ago
@jtrexr2
Then the x fields do not cancel and your summation would probably include an angle of some sort.
DanieleGiorgino 2 weeks ago
@9526772 its the integral not the derivative
ltethan649 1 month ago
isn't it the dy/dx of sin is cos ???
9526772 3 months ago
What if we want the electric field not in the center of the semicircular ring of charge, but below the x-axis. Say, y = -2?
jtrexr2 6 months ago
Hi and thanks a lot helped me a ton. I could not do it at the part of taking the derivative w.r.t the angle (I used to do it w.r.t length or radius. Thanks again.
darsheffect 11 months ago