Lec 26 | MIT 5.112 Principles of Chemical Science, Fall 2005

Loading...

Sign in or sign up now!
Alert icon
Upgrade to the latest Flash Player for improved playback performance. Upgrade now or more info.
9,055
Loading...
Alert icon
Sign in or sign up now!
Alert icon
There is no Interactive Transcript.

Uploaded by on Feb 14, 2008

Molecular Orbital Theory

View the complete course: http://ocw.mit.edu/5-112F05

License: Creative Commons BY-NC-SA
More information at http://ocw.mit.edu/terms
More courses at http://ocw.mit.edu

  • likes, 0 dislikes

Link to this comment:

Share to:

Top Comments

  • I am very grateful that MIT is doing these, Free knowledge is the best!

  • THIS IS AMAZING. HELPS A LOT

see all

All Comments (8)

Sign In or Sign Up now to post a comment!
  • 7 orbitals: 3 from hydrogens (1s), boron contributes 4 (2s, 2px, 2py, 2pz). Boron has only 1 'p' election, but the other empy p orbitals are still involved in forming the MOs.

  • search mo theory on here there a good video about it its called an introduction to molecular orbital or something like that.

  • Boron is a p block element. The electronic configuration is 1s(2) 2s(2) 2p(1) . The electrons in 1s orbital are core electrons. When we consider bonding, only valence electrons are considered.

    The total number of valence orbitals = 4

    One 2s orbital and three 2p orbitals.

  • But Boron still will not have filled valence electrons: 3+3=6. Is he missing the 2+ charge on the Boron or perhaps this is a special case?

  • It makes perfect sense. Boron has three valence electrons.  The 1s orbital isn't included because it is already filled and nested within 2s. So we have 2 of the valence electrons filling the 2s orbital. We have 1 electron left, which must go into the p-orbitals. If there are any electrons in the p-orbitals, all three orbitals are there. This doesn't, however, mean they all have to be filled. Therefore Boron has 4 orbitals: 2s, pz, py, & pz. With 2s being full and only 1 in the p's.

  • At 15:28, you say Boron has 4 valence orbitals. I thought that it only has 2 (which are 1s and 2s). Since you introduced the Shrodinger equation, you should have elaborated (i.e. H x wave function = E x wave function). My organic chemistry professor gave a lecture pretty similar to this... the whole pi and sigma orbitals did not make sense at all.

Loading...

Alert icon
0 / 00Unsaved Playlist Return to active list
    1. Your queue is empty. Add videos to your queue using this button:
      or sign in to load a different list.
    Loading...Loading...Saving...
    • Clear all videos from this list
    • Learn more