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Unsolvable Math Riddle (really!)

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Uploaded by on Dec 3, 2008

This riddle was solved by deadlybug.

Deadlybugs explanation:

"I don't see what's wrong with the riddle.

Write down all the possible trios that sum up to 13 - there are merely 14 of those.

Now write next to each one its product.

Each trio would have a unique product, except for two - 1,6,6 and 2,2,9 - which tells us that the answer is one of these (since the man gave a third clue).

2,2,9 is the one to have an eldest, so that would be the answer.

A pretty neat riddle (and a famous one as well)."

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  • likes, 8 dislikes

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Uploader Comments (eizhowa)

  • what is the seat number

  • @STARWARSMARC Thats kind of part of the riddle:)

  • @bonebaron not necessarily if you are technical in between twins one is still older by the other even if by mere seconds or minutes or possibly even hours.

  • @maltacool Yes, but it is a known fact that all parents with twins make the twins do everything together, and that if one twin gets to go to grandma the other one would complain and nag so much it would be sent too.

  • how can the seatnumber be 13, when the product of the children's age has to be 13? 1, 2 and 6,5?

  • @HaIolll I know, I thought I had updated the description. The correct answer is among the other comments, in case you'd like to attempt to solve it before I reveal it.

Top Comments

  • I don't see what's wrong with the riddle.

    Write down all the possible trios that sum up to 13 - there are merely 14 of those.

    Now write next to each one its product.

    Each trio would have a unique product, except for two - 1,6,6 and 2,2,9 - which tells us that the answer is one of these (since the man gave a third clue).

    2,2,9 is the one to have an eldest, so that would be the answer.

    A pretty neat riddle (and a famous one as well).

  • read these comments! everyones trying to write like smart asses :D

see all

All Comments (66)

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  • *ages

  • Ok umm, 13. and your seta is 13...6+4+3 is 13, maybe those are his children's agaes.

  • I HATE MATHS. THUMPS UP IF U AGREE!

  • Ok, the problem is that given the information in the riddle, we cannot come to the conclusion that two of the children are twins. But if you had said that the OLDER one went to his grandma for the first time, then everything would fit. Otherwise

    I have 3 children, the sum of their ages is 13

    C1=2y.o.

    C2=3y.o.

    C3=8y.o.

    The product is 2.3.8=48

    C3 is the eldest child. Everything fits. There are other possible cases as well, but in the version I suggested, these don't fit.

    Happy holidays!

  • This Is impossible because we dont know the seat number...

  • God yall niggas be dumbie. If the product = seat # and that number is that of the sum of their ages, you can induce that since 13 is prime meaning the only values that multiply to equal it are 1 and 13 their ages have to be 1, 1, 13. we have a problem lads! any other 3 values added up to 13 and then finding the product of their values will yield a different seat #. 9+2+2 = 13 9*2*2= 36 while 10*2*1 = 20. BUT WAIT! THERES A SOLUTION. 6*6*1 yields the same product as 9*2*2 but has an oldest child.

  • 10,2,1

  • You didn't actually give enough information: you have to tell us that the last fact is necessary for the other guy to figure it out. The original telling has the other guy saying "I still don't know what their ages are" in between the product clue and the eldest clue.

  • @CalebM1995 theres nothing saying that theres twins tho?

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