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Gracias.
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@lilangel0072 only if its cyclohexane or something where you can draw chair conformations.
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reagents get so friggin confusing
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i thought for E2 reactions the leaving H and Cl had to be antiperiplanar???
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@antonyfl Ionizing solvent doesnt matter when looking at basicity (only nucleophilicity) so this reaction is good enough to view E2 reactions
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the methoxy ion looks too bulky to attack the 3rd carbon to form zaitsev's product. Wouln't it make sense to for the methoxy ion to abstract a hydrogen from a primary carbon like carbon number 1, since it is not too sterically hindered, to form hoffman's product...giving a butene and not a but-2-ene molecule?
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Since the base is so strong, E2 will still occur here. Polar protic solvents CAN be used for E2/SN2 under the right conditions. Since polar protic solvents are much cheaper, this is actually how SN2/E2 is carried out industrially.
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Thank you! This video helped me get a problem right that I was having trouble on for two days.
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E2 requires antiperiplanar arrangement doesnt it?
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why is that H next to the carbon with the cholrine being knocked out?
Quick note Sal: This reaction isn't the best to show an E2 mechanism because the solvent is CH3OH, a polar protic solvent, which actually would favour SN1/E1 . I think a better solvent for this example would be DMSO
antonyfl 1 year ago 16
You should cover quantum mechanics after the chemistry is finished. You make difficult math concepts easy to understand so I imagine you can do QM very well.
dishonesttAbe 1 year ago 5