Hydroxy Ver. 1.6 Vacuum Test
Uploader Comments (Fordenergy)
All Comments (11)
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Yes, there is no more HHO produced under vacuum. The visual bubbles are simply larger per the ideal gas law: PV=nRT. The number of moles of hydrogen and oxygen produced is exactly the same as long at the current is constant. Production is a function of current only, since electrolysis requires free electrons.
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Umm, you really need to watch at 56 seconds, then fwd it to 2.44 and tell me there is no difference. the bubbles are going twice as fast.
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You are only putting the bubbler in a vacuum. Try putting a vacuum on the hho cell
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it's the same thing that ZFF came up with. Thanks for the work.
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As one has stated, the cell itself has to be under vacuum. Another youtube video shows this is the correct method. In the other video, the author dropped the vacuum to 25" of mercury on the cell itself.
Best Regards,
Dave
Have a Merry Christmas Everybody!
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Your cell was under vacuum. Maybe not as much as a car would deliver, but none the less the physics are the same. The vacuum will pull bubbles from the water, but not the cell it's self. If it could pull HHO off the cell it's self, then there would be no need for the electrolysis would there... Great work! I would like to collaborate with you on your findings. You can see my results so far on my posted video's.
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sorry to disagree but you might have better luck if you pressurize the cell itself-you should find that more energy is required for an equivelant reaction at normal pressure-wich leads me to beleive if you reduce the pressure in the cell less energy will be required for the reaction. i haven't plotted a graph for it so im not 100% sure on this but from what i've seen im convinced.
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Yes we are proving well known science is not complete. Meyer's did it in a big way. Now the way I tested the unit with a vacuum is at 30 mm hg at the max vacuum on a car. Gas production has to go up, it's is just chemistry. Trust me.
Take a look at over unit dot com of some of my post on this, I did the math. the vacuum has to be on the cell, not the bubbler. The math doesn't lie I have already proved vacuum elecetrolysis.
h2opower 4 years ago
Then explain why the vacuum on the cell is the same as the bubbler, and also explain at the beginning of the video how the bubbler pulled excess air from the cell. Therefore applying vacuum to the cell. The math may not lie but neither does the test. Watch when I start to apply vacuum, it equalizes the air pressure in the cell right along with the bubbler.
Fordenergy 4 years ago
If what you are saying is correct then there is no vacuum at all applied on the cell; which I know is not the case due to the air being pulled from the cell. Before this video my cell had a leak and it looked like my production was way up until I realized a seal on the (CELL) was leaking and feeding the bubbler. This test is after the cell leak was fixed and there was no difference in production under vacuum.
Fordenergy 4 years ago
But I may be wrong I'll wait to see the video in action to prove the math. After all we are proving science wrong aren't we?
Fordenergy 4 years ago
One last though after wating the video again. When I release the vacuum under 12V where is the water going? (the cell) because of the vacuum in the cell if there was no vacuum on that cell it wouldnt effect my feed tube.
Fordenergy 4 years ago