Modular arithmetic 2
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Uploader Comments (TheMathsters)
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Your lectures are great! I would love if I'd had more teachers like you in school.
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i love you.
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All Comments (16)
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i think im subscribing too!!
i wish my lecturer would go through this stuff, rather than assuming it is obvious
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I think.....
Im subscribing :)
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loveeee it!
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I have never seen a teacher as energetic as you.
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Its ok to say 5|x-y or 5|y-x since if a is congruent to b mod m then b is also congruent to a mod m.
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thank you!!! :D
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I was wondering, for the addition property, I think it is quite clear that x=y(mod n) is the same as x+a=y+a(mod n), i.e. the way I view it is that, they yield the same reminder when the difference is divided by n. I was wondering, for the second one, ax=ay(mod n), I know that n|x-y and that n|a(x-y), but does it yield the same remainder? and if it does, can u prove it does? my intuition tells me it does yield the same remainder, but Im not sure yet...
brandojazz 4 months ago
@brandojazz No: x-y and a(x-y) do not necessarily yield the same remainder when dividing by n. If x-y yield remainder r then a(x-y) will yield remainder ar. However, we only need to know that if x-y yield remainder 0 then a(x-y) also yield remainder 0.
TheMathsters 4 months ago
can i say "5|x-y" instead of "5|y-x"? i know they are the same but which one is the convention?
yejiahua 1 year ago
@yejiahua Yes it's fine to say either of those as they are equivalent. I was always taught second one as convention which is why I use it, but I can't think of a good reason for it.
TheMathsters 1 year ago