UHCL 23a Graduate Database Course - Minimal Covers Example
Uploader Comments (GaryBoetticher)
All Comments (30)
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For the final step, do you only look for redundant FDs with singles on the LHS? Still trying to form something containing the RHS in the closed set?
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Thank you very much for that video ! But I have a question, after doing all of these steps, will the minimal cover also be a boyce codd normal form ? Or is each left side of the FDs a key ?
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thank you so much professor...!! it was so helpful for me!..
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Thnx a lot Professor . You are a great person . It was very hard for me to understand that using my professor's lessons . Blessed are those who give without remembering.
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Excellent. Thank you.
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@kksandyrox You can always break an 'implies' statement down so that the left hand side implies each of the right hand sides individually.
So D-->AEH == D-->A, D-->E, D-->H.
Side Note:
It is NOT correct to say that: AEH-->D == A-->D, E-->D, H-->D.
The only exception is: AEH-->A == AE-->A == AH-->A == A-->A
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what if there are 3 elements on the right hand side? how to decompose and move forward? ex:
D-->AEH?
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You just saved my live. This was the ultimate help.
Just a short question: What should i do, if in the second step, when we eliminate the extraneous member of the left hand side, for example AB the left hand side, and the closure of A contain B and B closure contain A.
nxjohny 4 months ago in playlist GaryBoetticher videói
@nxjohny You may eliminate either the A or the B. Given a set of FDs, there may be 2 more minimal covers.
GaryBoetticher 4 months ago