Time & Work - Vidya Madam

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Uploaded by on Nov 10, 2009

Problems on time and work .

  • likes, 2 dislikes

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  • it is a very useful video..plz post videos on other chapters like distance,train..etc.u r teaching is simple and easy to understand..

  • its Question not Queshion.

  • mam if you will do like this than sure no chance in exam ,concept matters.

  • @WellConditionedChimp so 20 pigs * 7 days = 14 pigs * x days. x = 10. job2/job1 = 200/500. (2/5)*10 = 4

    finito

  • these problems can be solved much more easily like so: the number of actors (pigs, cops, etc.) is inversely proportional to the number of days necessary - in other words, the more actors there are working on a job, the less time is necessary.

    So, actor*time=actor*time. you solve for the unknown. the unknown is then multiplied by the ratio of the second job to the first. It's that easy

  • everybody here speak write english like asshole

  • Certainly this is great job, it was hard to find out for me!!!

  • i needed this video nw.....post more sums on time and work

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