simplifying expressions I
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Uploader Comments (robichaudd)
Top Comments
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wow ty so much, i think my algerbra teacher sucks kinda, she goes way to fast through the problems, i was trying to copy the problem down and shes already finishing up the problem and starting on a new one, its so annoying xD so yha this helps alot
2 years ago 8
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Thank you so much this helped so much more than my stupid subsitute teacher :)
2 years ago 5
All Comments (49)
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Great video! I am helping my 12yr old son with his homework and this vide was so helpful. Thank you!
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I have to simplify the expresion an write the property D:
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Thanks SO much! My math teacher gave us this worksheet for pre-algebra and I kept asking for help but she ignored me. I spent forever looking at tutorial videos but none of them helped. Now I actually get it. :)
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How do i Divide by 0???HELP! My calculator sucks and says ERROR now i don't work ):
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I hope you still see this since the upload is a few years old. Could you help with: simplify (8x)(2y)(3z) the next problem is the same only they all have to be added. How can this be done if there are no like kinds? Thank you
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Wasnt sure if would ever get this down.
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uhhhh i dont get it
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Omg thank u so much!
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I hope you can help. My problem is when finishing the simplification, I'm never sure if the number
with the variable goes first or after the number alone.
Example 1:
5 - 2 ( x + 2 [ 3 + x ] )
I got this wrong by solving as "-7-6x" when it should have been "-6x-7"
Example 2:
4 - 9 ( 2 x - 3 ) + 7 ( x - 1 )
I got this wrong by solving as "-11x+24" when it should have been "24-11x"
I assume I'm missing some rule, but I'm not sure what it is :(
Thanks in advance.
h1k3r99 2 months ago
@h1k3r99 Both ways of showing the answers are valid. When in doubt, the safest way to show an answer is with descending powers of the variable. So for -7-6x, show -6x-7. Not sure why your -11x+24 answer would be marked wrong. There might have been some detail in the problem that suggested leaving the answer in a certain format.
robichaudd 2 months ago
5+3(x-2) shouldn't it be 5x-10+3x-6 then 8x-16? cus i thought you had to distribute the 5 into x-2 and the 3 into x-2? wasn't that what was supposed to happen?
biggee316 10 months ago
@biggee316 In 5+3(x-2) the 5 is being added to 3(x-2), so first we multiply the 3 with (x-2), then add 5 to the result. If the expression was instead (5+3)(x-2), then both the 5 and 3 would multiply the (x-2) in the way you described in your comment.
robichaudd 10 months ago