1 + 1 = 0: The Proof!
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Jesus christ I come here and I see big equations trying to prove this guy wrong. This is how I do it. 1 x One wholeNumber times One more Whole Number Equals two Whole Numbers.
1 = One Whole Number.
So, Add another Whole One to it. Viola you have two Whole Numbers.
Math 101
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I am baffled.(period)
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sqrt[a] * sqrt[b] = sqrt[ab] is always true if and only if a and b are both positive. That's the problem with this equation.
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@TheHarboe Actually, it applies for any positive number a such that a = b*c where b,c are both positive AND for any negative number a such that a = b*c where b,c are both negative. :)
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WELL, WHEN I TRY TO SUM UP 1+1, I GET FREAKIN'
404 Forbidden
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I have one apple. I add another apple. I have two apples, not zero.
I win.
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@xouris123 you are absolutly right, but the definition still says that you can exchange the -1 in the sqrt with i^2, not that you can define i=sqrt(-1)
Of course it started in another way and practically, when calculating with it, it doesn`t matter, but it is still not defined as sqrt(-1)^^
1 + 1 = 0 if you use condom right :D
roni45ul 3 weeks ago 13
sqrt(1)=sqrt[(-1)(-1)] is true
sqrt[(-1)(-1)]=sqrt(-1) x sqrt(-1) is false
The last rule only applies to non-negative numbers, where -1 is clearly negative.
TheHarboe 3 weeks ago 10