Integration in polar coordinates | MIT 18.02SC Multivariable Calculus, Fall 2010

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Uploaded by on Jan 3, 2011

Integration in polar coordinates

Instructor: David Jordan

View the complete course: http://ocw.mit.edu/18-02SCF10

License: Creative Commons BY-NC-SA
More information at http://ocw.mit.edu/terms
More courses at http://ocw.mit.edu

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  • THANK YOUUUUUUUUUUUUU

  • @maplestorypl He wrote it correctly. dA becomes r dr dtheta so the integral does become 1 / r^2.

  • I don't know if someone already caught this but at 7:08, it's supposed to be 1/r^3, so the answer turns out to be a bit more complicated than the one he ended up with.

  • Great videos, David.  Thanks kindly!

  • great video

  • @PeaceUdo I may be too late, but the angle is based on those special triangles, and specifically in this case it's the 1-1-root2 triangle. Since you know its slope is 1, the triangle can be drawn and then you will notice that the maximum angle is pi/4

    Hope it helped.

  • @PeaceUdo

    Question a and b) The upper bound for y is y=x.

    The line y = x is always at a 45 degree (pi/4) angle with the x axis.

    If you dont get why, then for example lets say y = x = n (as y=x)

    then

    tan θ = n/n

    tan θ = 1

    therefore θ=45 degree (pi/4)

  • I just wish someone can explain how you know what theta is. How do you know its pi over four? Ugh

  • lets be real, no one did it on their own

  • @MyChatwin He is 28, but looks like 20! XD

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