Projectile motion
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1:02:38
Physics 210 - Lecture 7 - Projectile Motion from a horizontal cliffby UMKC9,589 views- 5:11
Projectile Motion Problemby jamdann211,866 views
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Physics Lesson: Projectile Motion Part 1 for High Schoolby PhysicsEH41,471 views
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Projectile Motion - Engineering Dynamicsby structurefree1,137 views
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Kinematics Lecture - Projectile Motion - page 17by thephysicscafe3,066 views
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Physics 3.5.2a - Projectile Motion Conceptsby derekowens81,093 views
- 7:36
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Projectile Motion, Launched from a Known Heightby bhswarthout2,816 views
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Free Fall Motionby bhswarthout3,869 views
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HSC Physics - Projectile Motion - Richard Shawby talent100education1,428 views
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Physics 3.5.3b - Example - A Piano is Thrown into the Airby derekowens6,860 views
For the finding the max height, if you use the equation V2 squared = v1 squared + 2a(delta)d.
And the projectile was launched at an angle that is NOT 45 degrees. Would you use V1 or V1y?
boohalala 1 week ago
@yomommasson111 thanks :)
pinkamh 4 weeks ago
@pinkamh It's mainly just a concept. At the beginning, he stated that the initial velocity of the rock was positive in the upward direction. So it makes sense to make something in the downward direction negative.
yomommasson111 1 month ago
could someone tell me why did the (Vy)f turn out to be -81.9 ??
how can it be negative if we got it from a square root ??
see it at (2min:20sec )
pinkamh 1 month ago
I had a similar question and was stuck. The question is as such; a stone is thrown (in projectile motion) with vertical speed u from a cliff of 30m high. it hits the ground(bottom of cliff) 5s later. What is the value of u? the solution to this problem includes taking s as -30 in s=ut+1/2at^2. the value of u was found straight forward. What is the logic behind. I dont understand that, help please.
prandtl002 3 months ago
Excellent video.
Thank you for such graphical and thorough explanation.
Rosanella :)
lillyvalleys 4 months ago