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Integration Using Inverse Trigonometric Functions - Ex 2

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Uploaded by on Jul 14, 2009

Integration Using Inverse Trigonometric Functions - Ex 2. In this video, I give two formulas and show how to solve a definite integral using u-substitution and the formulas.. For more free math videos, visit http://PatrickJMT.com

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Uploader Comments (patrickJMT)

  • When you plugged in u, you also said that -du=sinx dx. aren't you supposed to solve for dx? so, dx=-du/sinx. shouldn't you then plug in -du/sinx to replace the dx? you just plugged in du for dx. i'm confused.

  • @pgeske i never solve for dx when i do substitutions; just my style, some people do. algebraically it is all the exact same thing

  • hey patrick, will you marry me? ;)

  • @ILoveCristianoR i don't think my wife would approve of that : )

Top Comments

  • this guy does not ask for subscribers does not ask for money all he wants to do is just to help calc students. respect!

  • @Cooterstube i just did

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  • thanks :)

  • THANKS :)

  • @patrickJMT Ah, okay. great video!

  • how do you know which trig function to use for u? why did you choose cosine?

  • This video is very helpful...hope that you have also for addition integrals...

  • Your website is a goldmine!

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