Combustion Train Analysis

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Uploaded by on Dec 26, 2008

Determination of a compound's empirical formula from combustion analysis data is shown.

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Education

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  • After watching the video a second time, I noticed that the work is correct until the 5:42 mark. At that point, the work changes and is no longer correct.

  • The numbers on your slide appear to be incorrect. In the Nitrogen step, you have 1.036 g x 12.01 / 44.01. But it should be 14.01 / 46.01 as this is the mass of nitrogen and NO2. It appears that this fraction was copied from the carbon step. Your math is correct and your final answer is correct, but this slide does not show the correct work.

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