This Joule Thief work at a very very low input voltage from 0.125 to 0.35 volts and the output voltage is 2.7 volts, to the LED. An ordinary Joule Thief work down to 0.6 to 0.8 volts, because of losses in the transsistor. Voltage ratio is 1 to 21. So if the LED need 5 mAmps, the battery must give over 100 mAmps.
wonderful work you helped me and who does not thank people does not thank Allah so thank you very much go on
drmns 1 week ago
Well done, but
Where is the LED connected to ?
You are loosing the Basis current as the waste current.
Better use Dr. Jones circuit and try to adapt this to your principle.
Regards, Stefan.
freeenergynews 1 month ago in playlist More videos from Larskro
Impressive. I liked this. Will have to try to replicate it.
Thanks. Keep up the nice work
The ole shop tchr
u2btchr 2 months ago