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Cisco Training CCNA IP Addressing - Part 7

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Uploaded by on Jun 12, 2008

Another example of tricks using a lookup table to work out exam type questions

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Education

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  • likes, 6 dislikes

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  • This video, compared to the others, is really bad. It will makes lost so many time. the answer is really fast and simple. you have a subnet mask of 29 and the IP address is 32.

    So you have 32-29= 3 bits for the hosts.

    So you calcute 2^3=8 (2 position (0 or 1) for each of the 3 bits).

    Then you remove 2 because of the address of the network itself and the address of the multicast.

    So you have 8-2= 6 the final answer.

    To resume, to find the answer you just make:

    2^3-2

  • Who here is CCIE raise your hand. If not shut up and be glad for this free video.

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  • Thanks for this tutorial....

  • Everyone has different ways of learning, memorizing etc . I have found the various aspects of ip addressing to be difficult to learn, I believe the decimal to binary relationship is my achilles heel

    I have found the whole series of videos helpful. ANYWAY, to all of you rocket scientist critics

    who can calculate 32-29=3 in a heartbeat, the video was 6 minutes long not 60 ...barely longer than the moronic television commercials.... over and out

  • No disrespect for the gentleman but if you watch this video and try to understand IP addressing for the first time you will get very confused. I don't find it very helpful at all even I know this stuff and I guarantee that I'll be able to provide more easy way of understanding.

  • we can just calculate 2^3-2=6

  • Many thank you for your excellent work!

    greece

  • /user/XICMI#g/u

  • dont you know 2^3-2=6 ... your table - lol

  • @PCSJEFF That's true and easy enough, but that doesn't give you the lookup table that he was trying to show. If you were trying to figure out a bunch of these, it would be easy to make the table and then just quickly look at the table for the answers.

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