Leibniz quest for Pi pt1

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Uploaded by on Aug 25, 2007

In this 3-part video we follow Leibniz in his pursuit to find the area of a quater circle of unit radius via integration, trigonometry and series expansion. Simply amazing!

Hope you like it. Check out www.gaussianmath.com for a more indepth explanation.

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All Comments (24)

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  • @Patsan120

    ds need not be equal to OS or dx to OR; what is equal is their ratio

    (OS / OR ) = ( ds / dx )

    Gregg

  • @thefifthlord1

    surface area circle is PI * r * r

    if r = 1, surface area of quarter circle is PI / 4

    You mix up with circumference of circle. Circumference circle is 2 * r * PI. If r = 1, circumference is 2 * PI and

    half-circle (180 degrees) would be PI.

    Point of video is the find surface area (integration -> area under curve) under quarter circle, i.e. PI/4

    Gregg

  • bad audio, great class

  • Leibniz = laibnits

  • It's pronounced Laibnits, not Libnis...

  • pi/4 = 180/4 = 45 degrees not 90, pi/4 = 1/8th a circle.

  • 2:00

  • gooooooooooood tiiiiiiiiiiiiiiimesssssss!

    11:47 PM

  • 3:06AM

  • You actually get (1/2)y - int(xdy) ( both from zero to 1). Which gives you:

    (1/2)y(1) - integral (xdy, from 0 to 1). Now you can figure out y(1) by using the proportion x/2=y^2/(1+y^2) in part 3 . That's how you get y(1)=1.

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