Chemistry: Qualitative introduction to buffer solutions (acid/base chemistry). How to approximate logarithms and pHs without a calculator.
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(1) Buffers
(2) Continued
(3) Continued
(4) Continued
(5) Continued
(6) Logarithms
(7) Continued
(8) Continued
(9) p
(10) Continued
(11) Continued
(12) Continued. Summary
Does the reaction forming SO4(-) also have a spectator ion like the former reaction which produced CH3COO(-) and had Na(+) as the spectator ion??? Thank you
bgoodies 2 weeks ago in playlist More videos from freelanceteach
Good lecture!!!!
WongeneKIM 7 months ago
You are awesome!!!!
Thank you..
yulikobe 10 months ago
thank you very much!! you are a life saver!!! you really clarify every thing, i never had understood buffer solution. i will spread your words to my friends. thanks again.
nilrama1 1 year ago
pH=-log[H+]
I've never see the equation with hydronium before. pOH= -log[OH-]
He writes hydroxide as HO- in an earlier video.
P.S. A trick my teacher said to remmber this is to think of power of hydrogen and power of hydroxide when you think about pH and pOH.
BellaRay1993 1 year ago
@deltaforce when the h2so4 deprotonates the ch3coo will attract the proton let go by the h2so4. in effect sponging it up.
thedlangfactor 1 year ago
does all weak acids sponge up
deltaforce 2 years ago
why does the ch3coo sponge up
deltaforce 2 years ago