Boolean algebra #2: Basic problems

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Science & Technology

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• Boolean
• algebra
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• lesson
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• digital
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[Supermanu15]

im sorry, i am having trouble understanding the A + AB = A(1+B) part,what do u mean by moving them out of brackets?PLEASE HELP T_T

[keleshevCOM]

@Supermanu15 say, if you multiply A by (1+B):

first you multiply A by 1

then A by B

and sum them up - you got A*1 + AB witch is A + AB

that's why A(1 + B) = A + AB and vice versa :-)

when I say "taking A out of brackets" I mean that A in A+AB is a common factor (we have A in both terms - in A which is same as A*1, and in AB). So if we it's in both terms separately (A*1 + AB) or together A(1+B) the result is the same.

Hope it's clear. Please ask me more questions if something is not clear :-)

[Supermanu15]

@keleshevCOM that was clear as crystal!!!! :D thanks man!it took me a lot of time just gazing at the reason why it turned into A(1+B) like O_O..thanks for clearing up the fog teach,haha you'll be my online teacher now,since i always come late during class :D

[keleshevCOM]

@Supermanu15 You are welcome :-)

[shayan22h]

u should have answered her, buddy ;)

cheers, great vid.

[Deliryz]

Thank you SO MUCH for taking the time and making this videos, I understand everything now :D

[benkhin]

can you help me solve (A'+B'+C')*(A+B+C')



[308ma]

Thank you very much

[SuperXZElite]

helped me solve the question (x+y)' * (x'+y')

[MrJAlabaster]

OMG!!! You are a lifesaver!!!

[JinGabrielleFoliente]

that was genius. thanks keleshevCOM :D

[McGowanChris]

Great work thanks