Calculus I - Lecture 8 - Trigonometric Functions

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Uploaded by on Nov 11, 2009

This video contains the following topics (all times listed are approximate)

The 6 Trigonometric Functions: Continuous on Their Domains [4 min.]
When Inverses are Continuous [3 min.]
Finding a Limit by "Squeezing" [6 min.]
Limit Tales [1 min.]
Some Exercises [7.5 min.]
Solutions [5.5 min.]
Further Solutions [2 min.]

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Education

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  • @deugle yes he is wrong because 1-cos^2 (t) is is sin^2 (t) Which changes the problem to the type Lim t >> 0 of t / sin (t) * t / sin (t) which = 1

  • Wonderful series! However after trying a number of calculations and graphing the last exercise, I keep getting

    Lim (t^2/(1-cos(t)^2) = 1 as t goes to 0, instead of 0 as Prof. Delaware indicates.

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All Comments (9)

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  • The "squeezing" method is also sometimes called the sandwich theorem.

  • The last problem must be = 1 (not 0)

  • really good lecture. Thanks

  • very good  lecture

  • well guyz i jst gave the exams of matric class or 10th grade

    n thanks alot to this gr8 main becz of this i have learn 7lectures of calculus

    and i learned 2 years earlier becuz it is started frm Bsc in Pakistan :) :)

  • thank you! God bless :) <3

  • @mysteriousnyc another thing to notice is the result of lim x->0 [(1-cosx/x)) = 0/2=0 and lim x->0 [x/(1-cosx)] = 2/0=undefined. So, we cannot use it as the lim x->0 (sinx/x)=1 and its reciprocal.

  • Anybody here take high school math in the 60s or 70s with Houghton-Mifflin's math series by Mary Dolciani et. al.?

    I remember these books fondly and wish to purchase them: Algebra 1: Structure and Method (1967) ; Algebra 2 & Trigonometry; Math Analysis, and the pre-algebra 8th Grade text, the name of which I cannot remember.

    Did you dig these books, or what?

    Also, for math lovers, what other subjects do you love as much? Mine are physics and German.

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