1_8 Recursive Formulas for Sequences
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it confused me, when i was waiting for her to finish the first one, turning it into something useful for finding n=30 & she just went on with another example! (ca 2:46)
eventually i realized that it's pretty easy!
if 40 was ordered 1st (f(1)=40), we could simply use f(n)=80/2^n, for finding any n-th value on the sequence without calculating the preciting term! for instance f(8)=80/2^8=0.3125, or f(30)=80/2^30=7.450580597*10^-
08 thought that somebody might find my finding useful/interesting :)
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i fell asleep
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you're my savior thank you
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@Nscaamano because 2/3 of all paid teachers are fucking retards.
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THANK YOU I had a AIMS review in high school and i blanked out when i saw this now i get it
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thank uu
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For the first problem, could that sequence also be written in a geometric form, where r= 1/2?
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I Got Lost at 2:02
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i got lost at 2:00
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at first i kept ( dunno why ) thinking T(n-1) = (Tn)-1
till i realized the subscript was order, not value
(T(n)) is value, not n
then it makes sense
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the whole Tn=T(n-1) thing was throwing me off big time...but for some reason when you said "preceding term" everything just made sense. It's funny when one little explanation seems to almost unlock the problem
conn123456789 2 years ago 11
Thank You Very Much! Why can't my teacher be like you? :-)
Nscaamano 1 year ago 5