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numbers sequence 10-29-2011

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Uploaded by on Oct 28, 2011

Numbers Sequence game for 10-29-201, our Halloween version!

Guess the next number in this sequence of numbers.

Give up? Visit http://mathtricks.org for the answers.

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  • f(1)=0

    and

    f(n)=4*f(n-1)+13

    for every n positive integer from 2 till infinity

    the 8th number shown here is 70993,

    so the next (9th) number is f(9)=4*70993+13=283985

  • Ah! How can one figure this out?

    I said f(1) = 0, and f(2) = 13. Then,

    f(n) = f(n-2) + f(n-1) * (8 - n) which worked for the n= 3 and n =4... then fails.

    I read the answer on your website, but am wondering what a general method for determining the solution is... Fun stuff!

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