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Uploaded by FunMathTricks on Oct 28, 2011
Numbers Sequence game for 10-29-201, our Halloween version!Guess the next number in this sequence of numbers.Give up? Visit http://mathtricks.org for the answers.
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f(1)=0
and
f(n)=4*f(n-1)+13
for every n positive integer from 2 till infinity
the 8th number shown here is 70993,
so the next (9th) number is f(9)=4*70993+13=283985
9974388710035925 4 months ago
Ah! How can one figure this out?
I said f(1) = 0, and f(2) = 13. Then,
f(n) = f(n-2) + f(n-1) * (8 - n) which worked for the n= 3 and n =4... then fails.
I read the answer on your website, but am wondering what a general method for determining the solution is... Fun stuff!
hapybrian 4 months ago
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f(1)=0
and
f(n)=4*f(n-1)+13
for every n positive integer from 2 till infinity
the 8th number shown here is 70993,
so the next (9th) number is f(9)=4*70993+13=283985
9974388710035925 4 months ago
Ah! How can one figure this out?
I said f(1) = 0, and f(2) = 13. Then,
f(n) = f(n-2) + f(n-1) * (8 - n) which worked for the n= 3 and n =4... then fails.
I read the answer on your website, but am wondering what a general method for determining the solution is... Fun stuff!
hapybrian 4 months ago