Paul Wilmott on Quantitative Finance, Chapter 3, First Stochastic Differential Equation
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Uploader Comments (NathanWhitehead)
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All Comments (7)
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Thanks for explain in that way!!!! I can understand now :)
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can't believe i found ur vids now!! i could have aced my quant finance class if i had found it a few months earlier. love ur vids!!
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Thanks! helped clear that up
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at 3:07, the Ri*Ri+1 cancel. Can we say that this is because the expected value of it is 0? I think you showed that in the brownian motion video. Thanks for answering my questions!
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meybe i can help u with that a litle bit.
u can talk with me on skype-
look for alonsela972 from israel
:-)
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hi
u have an answer for u:
if z is a variable distrebuting normaly with 0 mean and std 1then:
x=z*dt^0.5 E[x] =E[z*dt^0.5]=E[z]*E[dt^0.5]=0
and VAR[z]=VAR[z*dt^0.5]=E[(z*dt^0.5)^2]-E^2[z*dt^0.5]=E[z^2*dt]-0=E[z^2]*[dt]=1*dt=dt
therefor x is a wiener process whith E[x]=0 and V[x]=dt
i hope it helps u
alon
alonsela972 1 year ago
@alonsela972 Thanks, that actually makes some sense. Although I still *almost surely* don't understand all the technical requirements of Wiener processes. That was almost a joke. ;)
NathanWhitehead 1 year ago