Alert icon
We're changing our privacy policy. This stuff matters.  Learn more  Dismiss

Solution to Problem 6: The Area of The Right Triangle

Loading...

Sign in or sign up now!
11,874
Loading...
Alert icon
Sign in or sign up now!
Alert icon

Uploaded by on May 1, 2008

I explain why right triangle with the parameters given does not exist.
---
If you like this video please subscribe to this channel and vorojtsov newletter at
http://www.vorojtsov.net
Thank you!
---

  • likes, 4 dislikes

Link to this comment:

Share to:

Uploader Comments (vorojtsov)

  • this is not the same triangle of the question...

  • why not?

Top Comments

  • why did you watch it then?

see all

All Comments (51)

Sign In or Sign Up now to post a comment!
  • @vorojtsov he just proved that it isn't a right triangle. so this "right triangle" doesnt exist because it doesn't have a 90 degree angle.

  • Or even easier. Draw a semicircle using the "hypotenuse" as a diameter. The radius of that circle is 5, and all right triangles formed with that line as a hypotenuse would have the opposing vertex on the circle (I think if you don't know this, it's easy enough to show). But if the opposite vertex of *your* triangle is 6 units above the hypotenuse, it cannot lie on the circle, and thus, cannot form a right angle.

  • and if we generalize the equation :

    x² - 10x + 36 = 0 by a relation between

    the Base(10 in the example) and Height(6 in the example) we find

    x² - B² x+ H² = 0 and only one solution

    when B²=4H² so if Base = 10 the Height must be equal 5 and if the Height equal 6 then Base must be 12 (generally B=2H) that it's false in the example you shown so this right triangle don't exists.

  • I am ashamed. That was very enlightening.

  • you look like you are a smart guy! but jesus the way you speak english! gosh!!!!

  • ???

  • say what

  • cool. i didnt even understand the problem at the beginning but well, its not that difficult :)

  • con't... In this larger circle (actually it's an oval, because the base of the triangle is still 10) we have the same properties as before. We can move the point around the hyperbolic shape of the oval, and still get a triangle.

    We cannot however, get the shape drawn in the video because, like before, as X increases, Y decreases, and in the video, the second triangle is exactly the same height as the first inscribed in the oval. Imagine a triangle where SideA=2, SideB=2 and SideC=20,000.

View all Comments »
Loading...

0 / 00Unsaved Playlist Return to active list
    1. Your queue is empty. Add videos to your queue using this button:
      or sign in to load a different list.
    Loading...Loading...Saving...
    • Clear all videos from this list
    • Learn more