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Titration Calculations

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Uploaded by on Apr 4, 2008

A worked solution involving a titration of NaOH with HCl. Find out the molarity of an unknown solution.

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  • Easiest shit ever

  • FUck Chemistry!

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  • Thank you :) Thank you :) Thank you :) Thank you :) Thank you :) Thank you :)

    Thanks a million times

    I wish I had you as my teacher

  • Its alright to use the formula n=cv without dividing by a 1000 as long as both your solutions volumes have the same units (in this case ml) as the volumes would actually get divided by each other so there's no point in converting units in this particular case, as Cx.Vx/Cy.Vy=a/b .. (Cx= concentration of the acid, Vx= volume of the acid, Cy= concentration of the base, Vy= volume of base, a= number of moles of the reacting acid, b= number of moles of the reacting base).

  • i fuckin love you sir

  • @amirsthebest12 sorry if its in cm3 which is normally in titrations you dont use the equation n=cxv.. its n=cxv/1000 !!!

  • Thank you!! When times seemed so bleak and the chemistry exam edged nearer...I found this that cleared things up 8D

  • step 1: write out all the info you know for the known:

    e.g. c=1.0244... v=3445 etc etc from the question write the key parts down.

    step 2: work out moles of known: (HCI) n=cxv

    step 3: use ratio to reveal the moles of the unknown from the known (e.g) 1 mole of hci reacts with 2 moles of naoh etc..

    step4: finally rearrange the n=cxv formula to get c=n (divided) by V, and you get your answer!

    recap: 1)write known values down 2)Work out moles of Known 3) Ratio them to help find unknown moles 4)C=nDv

  • erm in the 3rd step shouldn't the subject be v=c/n?

    im sorta confused on how you got 0.0250?

    if you'd just clearify please? x

  • already in dm-3?

  • @MassiusClay7 he did it

  • @MassiusClay7 1L=1000mL

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