L'Hopital rule indeterminate form involving both x and y
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Uploader Comments (midnighttutor)
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All Comments (16)
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midnighttutor...catchy i like it :)
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thank you now i got how to solve the indeterminate limits thnkx!!!!!!!!
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what does x approach?
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No, you should take the derivative of (x+y+2)^(1/2) with respect to y, so it's the same as the derivative of (constant + y)^(1/2) with respect to y so you would get what he said.
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No, I think he's confusing it with related rates but when I do that differentiation you did with respect to y, I get the same thing so you are in fact, correct my good man.
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equals..what :|
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How about x^x=5?
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hardest math evah..
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when you're taking the derivative of (x+y+2)^(1/2) you take the derivative of the y and the 2 with respect to y but what happens to the x? Implicit differentiation? should there not also be a dx/dt in there?
commyforever 3 years ago
No it is not assumed that y is a function of x or vice-versa. x is just a constant. Also at no time did a t term ever come up so not sure where you are getting that.
midnighttutor 3 years ago