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Inverse Trigonometric Functions - Derivatives - Example 3

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Uploaded by on Oct 25, 2008

Inverse Trigonometric Functions - Derivatives. A harder example.
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Uploader Comments (patrickJMT)

  • patrick Got me fallin inlove with calculus <3

  • @jackxzx awesome : )

  • wow

  • world of warcraft? : )

    i am a level 24 paladin elf-mage with a +20 longbow

  • whoa that was a hard problem, lol thank you!

  • ya! pretty loooooooooooooooooooong!

    but straight-forward... just long : )

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All Comments (42)

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  • 2:50 THAT'S WHAT SHE SAID ;)

  • Surprising how many math geniuses are left handed xDD all of my math teachers were

  • Thank you for not being lazy...this one was neat :)

  • Holy son of a gun. That was long.

  • @mush352 yeah my book and teacher does it that way, it takes up less space and easier to remember. like if you accidentally forget to multiply by the derivative of the inside, the whole problem is wrong.....

  • i always struggle with simplification.

  • how did you get from 1+sin^2x - cos^2x to 1+ 2sinx + sin^2x - cos^2x?

  • stupid me, i got it. thanx

  • in my class n text books, the derivative of an inverse function chained to anada function is the derivative of the inner function over the accompanied derivatv of the inverse function... such that d/dx arcsin(cosx/1+sinx)= (cosx/1+sinx)'/sqr(1-(cosx/1+s­inx)^2)

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