Subnetting Made Easy Part 1
Uploader Comments (NexGenT)
All Comments (42)
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Very helpful. Thank you!
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I don't think what you are asking can be done. 177.177.200.0/25 = 177.177.200. 0 255.255.255.128. Therefore network ranges will be in multiples of 128. Range is 177.177.200.0 to 177.177.200.127. But remember you can't use Network or Broadcast address. 128 - 2 = 126 useable addresses. You can't subnet this in 3 equal ranges. You can subnet into 4 to get the 2 /28s which would give you 16 (14 useable) you are requesting.
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Anyone who understands this method, please do a class A and B version using this method.
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Thank you. very helpful
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@kenchi9999 .127 network is the loop back network. Google loopback and you can read about it.
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Can you illustrate an example using a Class B or A?
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@cpaloukas91 is there a reason why 127 of all the ranges reserved for local host...and what exactly do u mean by local host?
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@kenchi9999 127.0.0.0 - 127.255.255.255 is reserved for 'local host.'
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how is class A ranged between 0-126 and B 128 to 191? Where is the 127????
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Can sumone plz solve this for me
1) You were given the address range 177.177.200.0, with subnet mask of 255.255.255.128
a) how many IPs are in the range?
b) how many usuable IPs are there in the range?
c) divide this range into 3 subranges with the first two ranges having 16 IPs. Calculate the following:
- Subnet masks of the 3 subranges
- Network and broadcast addresses of the 3 subranges
@WillyDrucker - the usable IP range for this subnet is 192.168.1.1 to 192.168.1.62 (62 IP addresses). With 192.168.1.63 being the broadcast address. Some material may reference the router interface IP address as a reservation which would mean there are 61 IP addresses left after assigning one to the router. However, the total number of IP addresses in any subnet with a 26 bit mask is 62 usable IP addresses
NexGenT 1 year ago