College Algebra- Graph Parabolas-VideoMathTeacher.com
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Uploaded by thegarydavis999 on Dec 17, 2008
This video demonstrates how to graph parabolas and find their vertexes in College Algebra.
Find math problems and the video solutions at www.videomathteacher.com
- 36 likes, 2 dislikes
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Uploader Comments (thegarydavis999)
Top Comments
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Finally, i wish you were my teacher hhahahaha. teachers at school are so confusing!
2 years ago 8
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nice handwriting! ^^ awesome vid!! thx!
2 years ago 5
All Comments (36)
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HAHAHA, im getting this in 9th grade.
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this can't be college algebra o_o i'm getting this in precalculus in 12th grade
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@InuMS this makes you cool right?
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Forget this retarded textbook videos over youtube are where its at!!!! Thanks for the vid this helped me pass my exam!
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College , I'm studying this in 9th grade .
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if the equation is a^2 - 25 = 0, the B would be 0 right? since there is no B? and x will become 0 as well?
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i need big help on y= -3x^2-9x+30..... how can i solve this?
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I'm learning this is 10th grade algebra I -_-
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are you serious????? I am learning this in 7th grade but then again, I go to a private school
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@ThrustRC Sadly, it is. They teach you this in a more confusing way so you THINK it's a super difficult class until you youtube it and remember learning it in 8th grade.
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I need help understanding
y(x)=x^2+4x-3
What do I do with the 4x?
ArkansasItalianBoy 2 years ago
Well, I'm not sure what your question refers to, but most of us would say something like "complete the square"? If so, divide the middle coefficient by 2 and square the result, the BOTH add and subtract the result.
So, y(x)=x^2+4x-3
y(x)=x^2+4x+(4/2)^2 - (4/2)^2 -3
y(x)=x^2+4x+2^2 - 2^2 - 3
y(x)=x^2 + 4x + 4 - 4 - 3
(factor the first 3 terms as a perfect square trinomial)
y(x) = (x+2)^2 - 7
So, if you were looking for the vertex it's (-2,-7) and goes up. Check out more at my website
thegarydavis999 2 years ago
Thanks much! My only hope is to help everyone understand mathematics better.
thegarydavis999 2 years ago